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0.81t^2=2.5
We move all terms to the left:
0.81t^2-(2.5)=0
We add all the numbers together, and all the variables
0.81t^2-2.5=0
a = 0.81; b = 0; c = -2.5;
Δ = b2-4ac
Δ = 02-4·0.81·(-2.5)
Δ = 8.1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{8.1}}{2*0.81}=\frac{0-\sqrt{8.1}}{1.62} =-\frac{\sqrt{}}{1.62} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{8.1}}{2*0.81}=\frac{0+\sqrt{8.1}}{1.62} =\frac{\sqrt{}}{1.62} $
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